SAP - Pass-Sure C_ABAPD_2309 - Latest SAP Certified Associate - Back-End Developer

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SAP C_ABAPD_2309 Exam Syllabus Topics:

Topic	Details
Topic 1	ABAP SQL and code pushdown: It discusses ABAP SQL, arithmetic expressions, manage dates, and create joins.
Topic 2	ABAP RESTful Application Programming Model: This topic explains the ABAP Restful Application Programming model, ABAP development, and the architecture of the ABAP Restful Application Programming model.
Topic 3	Core ABAP programming: This topic covers ABAP data types, the ABAP dictionary, modularization, exceptions, and logical expressions, operator precedence.

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SAP Certified Associate - Back-End Developer - ABAP Cloud Sample Questions (Q59-Q64):

NEW QUESTION # 59
In this nested join below in which way is the join evaluated?

A. From the top to the bottom in the order of the on conditions
1.
b is joined with c
2.
a is joined with b
B. From the left to the right in the order of the tables:
1.
a is joined with b
2.
b is joined with c
C. From the bottom to the top in the order of the on conditions:
1.
a is joined with b
2.
b is joined with c
D. From the right to the left in the order of the tables:
1.
b is joined with c.
2.
b is joined with a.

Answer: A

Explanation:
The nested join is evaluated from the top to the bottom in the order of the ON conditions. This means that the join expression is formed by assigning each ON condition to the directly preceding JOIN from left to right. The join expression can be parenthesized implicitly or explicitly to show the order of evaluation. In this case, the implicit parentheses are as follows:
SELECT * FROM (a INNER JOIN (b INNER JOIN c ON b~c = c~c) ON a~b = b~b) This means that the first join expression is b INNER JOIN c ON b~c = c~c, which joins the columns of tables b and c based on the condition that b~c equals c~c. The second join expression is a INNER JOIN (b INNER JOIN c ON b~c = c~c) ON a~b = b~b, which joins the columns of table a and the result of the first join expression based on the condition that a~b equals b~b. The final result set contains all combinations of rows from tables a, b, and c that satisfy both join conditions.

NEW QUESTION # 60
What are some of the reasons that Core Data Services are preferable to the classical approach to data modeling? Note: There are 2 correct answers to this question.

A. They transfer computational results to the application server.
B. They compute results on the application server.
C. They avoid data transfer completely.
D. They implement code pushdown.

Answer: A,D

Explanation:
Core Data Services (CDS) are preferable to the classical approach to data modeling for several reasons, but two of them are:
They implement code pushdown. Code pushdown is the principle of moving data-intensive logic from the application server to the database server, where the data resides. This reduces the data transfer between the application server and the database server, which improves the performance and scalability of the application. CDS enable code pushdown by allowing the definition of semantic data models and business logic in the database layer, using SQL and SQL-based expressions1.
They transfer computational results to the application server. CDS allow the application server to access the data and the logic defined in the database layer by using Open SQL statements. Open SQL is a standardized and simplified subset of SQL that can be used across different database platforms. Open SQL statements are translated into native SQL statements by the ABAP runtime environment and executed on the database server. The results of the computation are then transferred to the application server, where they can be further processed or displayed2.

NEW QUESTION # 61
What are advantages of using a field symbol for internal table row access? Note: There are answers to this question.

A. Using a field symbol is faster than using a work area.
B. A MODIFY statement to write changed contents back to the table is not required.
C. The row content is copied to the field symbol instead to a work area
D. The field symbol can be reused for other programs.

Answer: A,B

Explanation:
A field symbol is a pointer that allows direct access to a row of an internal table without copying it to a work area. Using a field symbol for internal table row access has some advantages over using a work area, such as12:
A MODIFY statement to write changed contents back to the table is not required: This is true. When you use a work area, you have to copy the row content from the internal table to the work area, modify it, and then copy it back to the internal table using the MODIFY statement. This can be costly in terms of performance and memory consumption. When you use a field symbol, you can modify the row content directly in the internal table without any copying. Therefore, you do not need the MODIFY statement12.
Using a field symbol is faster than using a work area: This is true. As explained above, using a field symbol avoids the overhead of copying data between the internal table and the work area. This can improve the performance of the loop considerably, especially for large internal tables. According to some benchmarks, using a field symbol can save 25-40% of the runtime compared to using a work area12.
You cannot do any of the following:
The field symbol can be reused for other programs: This is false. A field symbol is a local variable that is only visible within the scope of its declaration. It cannot be reused for other programs unless it is declared globally or passed as a parameter. Moreover, a field symbol must have the same type as the line type of the internal table that it accesses. Therefore, it cannot be used for any internal table with a different line type12.
The row content is copied to the field symbol instead to a work area: This is false. As explained above, using a field symbol does not copy the row content to the field symbol. Instead, the field symbol points to the memory address of the row in the internal table and allows direct access to it. Therefore, there is no copying involved when using a field symbol12.

NEW QUESTION # 62
You want to define the following CDS view entity with an input parameter:
Define view entity Z_CONVERT With parameters currency : ???
Which of the following can you use to replace "???? Note: There are 2 correct answers to this question.

A. A built-in ABAP Dictionary type
B. A data element
C. built-in ABAP type
D. A component of an ABAP Dictionary structure

Answer: B,C

Explanation:
Explanation
The possible replacements for "???" in the CDS view entity definition with an input parameter are A. built-in ABAP type and C. A data element. These are the valid types that can be used to specify the data type of an input parameter in a CDS view entity. A built-in ABAP type is a predefined elementary type in the ABAP language, such as abap.char, abap.numc, abap.dec, etc.A data element is a reusable semantic element in the ABAP Dictionary that defines the technical attributes and the meaning of a field12. For example:
The following code snippet defines a CDS view entity with an input parameter currency of type abap.cuky, which is a built-in ABAP type for currency key:
Define view entity Z_CONVERT With parameters currency : abap.cuky as select from ... { ... } The following code snippet defines a CDS view entity with an input parameter currency of type waers, which is a data element for currency key:
Define view entity Z_CONVERT With parameters currency : waers as select from ... { ... } You cannot do any of the following:
B: A built-in ABAP Dictionary type: This is not a valid type for an input parameter in a CDS view entity. A built-in ABAP Dictionary type is a predefined elementary type in the ABAP Dictionary, such as CHAR, NUMC, DEC, etc. However, these types cannot be used directly in a CDS view entity definition. Instead, they have to be prefixed with abap.to form a built-in ABAP type, as explained above12.
D: A component of an ABAP Dictionary structure: This is not a valid type for an input parameter in a CDS view entity. A component of an ABAP Dictionary structure is a field that belongs to a structure type, which is a complex type that consists of multiple fields.However, an input parameter in a CDS view entity can only be typed with an elementary type, which is a simple type that has no internal structure12.
References:1:ABAP CDS - SELECT, parameter_list - ABAP Keyword Documentation - SAP Online Help2:ABAP Data Types - ABAP Keyword Documentation - SAP Online Help

NEW QUESTION # 63
What are some characteristics of secondary keys for internal tables? Note: There are 3 correct answers to this question.

A. Multiple secondary keys are allowed for any kind of internal table.
B. Secondary keys must be chosen explicitly when you actually read from an internal table.
C. Sorted secondary keys do NOT have to be unique.
D. Secondary keys can only be created for standard tables.
E. Hashed secondary keys do NOT have to be unique.

Answer: A,B,C

Explanation:
Secondary keys are additional keys that can be defined for internal tables to optimize the access to the table using fields that are not part of the primary key. Secondary keys can be either sorted or hashed, depending on the table type and the uniqueness of the key. Secondary keys have the following characteristics1:
A) Secondary keys must be chosen explicitly when you actually read from an internal table. This means that when you use a READ TABLE or a LOOP AT statement to access an internal table, you have to specify the secondary key that you want to use with the USING KEY addition. For example, the following statement reads an internal table itab using a secondary key sec_key:
READ TABLE itab USING KEY sec_key INTO DATA(wa).
If you do not specify the secondary key, the system will use the primary key by default2.
B) Multiple secondary keys are allowed for any kind of internal table. This means that you can define more than one secondary key for an internal table, regardless of the table type. For example, the following statement defines an internal table itab with two secondary keys sec_key_1 and sec_key_2:
DATA itab TYPE SORTED TABLE OF ty_itab WITH NON-UNIQUE KEY sec_key_1 COMPONENTS field1 field2 sec_key_2 COMPONENTS field3 field4.
You can then choose which secondary key to use when you access the internal table1.
D) Sorted secondary keys do NOT have to be unique. This means that you can define a sorted secondary key for an internal table that allows duplicate values for the key fields. A sorted secondary key maintains a predefined sorting order for the internal table, which is defined by the key fields in the order in which they are specified. For example, the following statement defines a sorted secondary key sec_key for an internal table itab that sorts the table by field1 in ascending order and field2 in descending order:
DATA itab TYPE STANDARD TABLE OF ty_itab WITH NON-UNIQUE SORTED KEY sec_key COMPONENTS field1 ASCENDING field2 DESCENDING.
You can then access the internal table using the sorted secondary key with a binary search algorithm, which is faster than a linear search3.
The following are not characteristics of secondary keys for internal tables, because:
C) Hashed secondary keys do NOT have to be unique. This is false because hashed secondary keys must be unique. This means that you can only define a hashed secondary key for an internal table that does not allow duplicate values for the key fields. A hashed secondary key does not have a predefined sorting order for the internal table, but uses a hash algorithm to store and access the table rows. For example, the following statement defines a hashed secondary key sec_key for an internal table itab that hashes the table by field1 and field2:
DATA itab TYPE STANDARD TABLE OF ty_itab WITH UNIQUE HASHED KEY sec_key COMPONENTS field1 field2.
You can then access the internal table using the hashed secondary key with a direct access algorithm, which is very fast.
E) Secondary keys can only be created for standard tables. This is false because secondary keys can be created for any kind of internal table, such as standard tables, sorted tables, and hashed tables. However, the type of the secondary key depends on the type of the internal table. For example, a standard table can have sorted or hashed secondary keys, a sorted table can have sorted secondary keys, and a hashed table can have hashed secondary keys1.

NEW QUESTION # 64
......

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